kinetics/equilibrium

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MASS-ACTION EXPRESSION (EQUILIBRIUM CONSTANT)

 

For the reaction aB + bB <---> cC + dD            Keq = [C]c [D]d / [A]a [B]b

 

Note: Solids and liquids have constant concentration therefore they do not appear in Keq

Example

BF3(g) + 3H2O(l) <---> 3HF(aq) + H3BO3(aq)     Keq = [HF]3 [H3BO3] / [BF3]

 

The K eq of a reverse reaction is the reciprocal of the forward reaction.

Example:

Keq of forward reaction is 1 x 10-11 than the reverse reaction Keq is 1 / 1 x 10-11

 

Solubility Product Constant (Ksp)

Used for salts.

Example:

PbCl2(s) ---> Pb2+(aq) + 2Cl-(aq)             Ksp = [Pb2+] [Cl-]2

 

LAWS OF THERMODYNAMICS

 

The first Law of Thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

 

∆E = q − w

 

q = heat added to the system

w = work done by the system on the surroundings

 

The Second Law of Thermodynamics states that in any spontaneous process there is always an increase in the entropy of the universe.            

       

                ∆S universe = S system + S surrounding

 

The Third Law of Thermodynamics states that a crystal at 0 K has 0 entropy.

 

GIBBS FREE ENERGY

The function G (free energy) is used to find the spontaneity of a reaction.

            ∆G = ∆H-T∆S     T in Kelvin

 

When ∆G < 0 the forward reaction is spontaneous therefore reactants form products.

When ∆G > 0 the reverse reaction is spontaneous therefore products form reactants.

When ∆G = 0 the reaction is at equilibrium

 

 

 

Summary

 

Spontaneity

∆G

=

∆H

-

T

∆S

Case #1

forward

-

 

-

 

all

+

Case #2

forward

-

 

+

 

high

+

Case #3

forward

-

 

-

 

low

-

Case #4

reverse

+

 

+

 

all

-

 

RATE LAWS

Most chemical reaction rates vary with the concentration of the reactants. The rate law of a reaction is only determined by experiment.

 

                In first order reactions (k[A]1), as concentration changes the rate changes in the same way.

                In second order reactions (k[A]2), as concentration changes the change in rate is the square of the concentration change.

                In zero order reactions (k[A]0 = k), as concentration changes the rate is constant.

 

k = a proportionality constant

A = a reactant in a reaction

 

Example

What is the rate law for the reaction 2NO(g) + 2H2(g) --> N2(g) + 2H2O(g) given the following data?

 

Run

Reactants Concentration

(mol/L)

Rate of reaction

[NO]

[H2]

1

0.10

0.010

0.062

2

0.10

0.040

0.246

3

0.30

0.010

0.558

 

 

First, write the rate law for the reaction

Rate = k[NO]n [H2]m

 

Second, calculate “n”

Find the runs where [H2] remains constant

 

Comparing run 1 and 3

 

Δ [NO]

Δ rate

n

Rate law

3 times

(0.30/0.10) = 3

9 times

(0.558/0.062) = 9

3n = 9

therefore, n = 2

k[NO]2

 

Third, calculate “m”

Find the runs where [NO] remains constant

 

Comparing run 1 and 2

 

Δ [H2]

Δ rate

m

Rate law

4 times

(0.040/0.010) = 4

 

4 times

(0.246/0.062) = 4

 

4m = 4

therefore, m = 1

k[H2]1

 

Therefore, the rate law for the reaction is

Rate = k[NO]2 [H2]1

 

Problem

The following data was obtained for the reaction 2A(g) + B2(g) --> 2C(g)

Run

[A]

[B2]

Rate (mol/L.s)

1

2

2

4

2

4

2

16

3

2

8

16

What is the rate law for the reaction?

 


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